20 Essential Python Tricks to Boost Readability and Efficiency
This article presents twenty practical Python techniques—including string reversal, title casing, unique element extraction, list multiplication, dictionary merging, and performance timing—to boost code readability, reduce redundancy, and enhance development efficiency for developers.
Python’s readability and simplicity make it a favorite language, and the following twenty tricks can help you write cleaner, more efficient code while saving valuable time.
1. String reversal
# Reversing a string using slicing
my_string = "ABCDE"
reversed_string = my_string[::-1]
print(reversed_string) # EDCBA2. Capitalize the first letter of each word
my_string = "my name is chaitanya baweja"
new_string = my_string.title()
print(new_string) # My Name Is Chaitanya Baweja3. Find unique characters in a string
my_string = "aavvccccddddeee"
temp_set = set(my_string)
new_string = ''.join(temp_set)
print(new_string) # cdvae4. Repeat a string or list n times
n = 3 # number of repetitions
my_string = "abcd"
my_list = [1, 2, 3]
print(my_string * n) # abcdabcdabcd
print(my_list * n) # [1, 2, 3, 1, 2, 3, 1, 2, 3]5. List comprehension to multiply each element
original_list = [1, 2, 3, 4]
new_list = [2 * x for x in original_list]
print(new_list) # [2, 4, 6, 8]6. Variable swapping
a = 1
b = 2
a, b = b, a
print(a) # 2
print(b) # 17. Split a string into a list of substrings
string_1 = "My name is Chaitanya Baweja"
string_2 = "sample/ string 2"
print(string_1.split()) # ['My', 'name', 'is', 'Chaitanya', 'Baweja']
print(string_2.split('/')) # ['sample', ' string 2']8. Join a list of strings into a single string
list_of_strings = ['My', 'name', 'is', 'Chaitanya', 'Baweja']
print(','.join(list_of_strings)) # My,name,is,Chaitanya,Baweja9. Check if a string is a palindrome
my_string = "abcba"
if my_string == my_string[::-1]:
print("palindrome")
else:
print("not palindrome")10. Count occurrences of elements in a list
from collections import Counter
my_list = ['a','a','b','b','b','c','d','d','d','d','d']
count = Counter(my_list)
print(count) # Counter({'d': 5, 'b': 3, 'a': 2, 'c': 1})
print(count['b']) # 3
print(count.most_common(1)) # [('d', 5)]11. Determine if two strings are anagrams
from collections import Counter
str_1 = "acbde"
str_2 = "abced"
str_3 = "abcda"
cnt_1, cnt_2, cnt_3 = Counter(str_1), Counter(str_2), Counter(str_3)
if cnt_1 == cnt_2:
print('1 and 2 anagram')
if cnt_1 == cnt_3:
print('1 and 3 anagram')12. Use try‑except‑else‑finally for error handling
a, b = 1, 0
try:
print(a / b)
except ZeroDivisionError:
print("division by zero")
else:
print("no exceptions raised")
finally:
print("Run this always")13. Enumerate a list to get index/value pairs
my_list = ['a','b','c','d','e']
for index, value in enumerate(my_list):
print(f"{index}: {value}")14. Check object memory usage
import sys
num = 21
print(sys.getsizeof(num)) # 28 in Python 315. Merge dictionaries
dict_1 = {'apple': 9, 'banana': 6}
dict_2 = {'banana': 4, 'orange': 8}
combined_dict = {**dict_1, **dict_2}
print(combined_dict) # {'apple': 9, 'banana': 4, 'orange': 8}16. Measure execution time of a code block
import time
start_time = time.time()
for i in range(10**5):
a, b = 1, 2
c = a + b
end_time = time.time()
time_taken_in_micro = (end_time - start_time) * 10**6
print(time_taken_in_micro)17. Flatten a nested list
def flatten(l):
return [item for sublist in l for item in sublist]
l = [[1,2,3],[3]]
print(flatten(l)) # [1, 2, 3, 3]
# Using iteration_utilities for deeper nesting
from iteration_utilities import deepflatten
l = [[1,2,3],[4,[5],[6,7]],[8,[9,[10]]]]
print(list(deepflatten(l, depth=3))) # [1,2,3,4,5,6,7,8,9,10]18. Randomly sample elements from a list
import random
my_list = ['a','b','c','d','e']
num_samples = 2
samples = random.sample(my_list, num_samples)
print(samples) # e.g., ['a', 'e']19. Convert an integer into a list of its digits
num = 123456
list_of_digits = list(map(int, str(num)))
print(list_of_digits) # [1, 2, 3, 4, 5, 6]
# or using list comprehension
list_of_digits = [int(x) for x in str(num)]
print(list_of_digits)20. Check if all elements in a list are unique
def unique(l):
if len(l) == len(set(l)):
print("All elements are unique")
else:
print("List has duplicates")
unique([1,2,3,4]) # All elements are unique
unique([1,1,2,3]) # List has duplicatesAt the end of the article, promotional material invites readers to scan a QR code to receive free Python learning resources, including e‑books, tutorials, and source code collections.
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