5 Practical JavaScript Tricks to Write Cleaner Conditional Logic
This article presents five useful JavaScript techniques—using Array.includes, early returns, default parameters with destructuring, object literals or Map instead of switch, and Array.every/Array.some—to simplify and make conditional statements more readable and maintainable.
1. Use Array.includes for multiple matching criteria
Replace long || chains with Array.includes to test if a value is in a list.
function test(fruit) {
if (['apple', 'strawberry', 'cherry', 'cranberries'].includes(fruit)) {
console.log('red');
}
}2. Reduce nesting with early return
Validate inputs early and exit the function when a condition fails, flattening control flow.
function test(fruit, quantity) {
if (!fruit) throw new Error('No fruit!');
if (!['apple', 'strawberry', 'cherry', 'cranberries'].includes(fruit)) return;
if (quantity > 10) console.log('big quantity');
else console.log('red');
}3. Use default parameters and destructuring
Assign default values directly in the function signature and destructure objects to avoid repetitive null checks.
// default parameter
function test(fruit, quantity = 1) {
if (!fruit) return;
console.log(`We have $${quantity} ${fruit}!`);
}
// destructuring with default empty object
function test({ name } = {}) {
console.log(name || 'unknown');
}4. Replace switch with object literals or Map
Use an object literal or a Map for key‑to‑value lookups instead of a switch statement.
// object literal lookup
const fruitColor = {
red: ['apple', 'strawberry'],
yellow: ['banana', 'pineapple'],
purple: ['grape', 'plum']
};
function getFruitsByColor(color) {
return fruitColor[color] || [];
}
// Map version
const fruitMap = new Map();
fruitMap.set('red', ['apple', 'strawberry']);
fruitMap.set('yellow', ['banana', 'pineapple']);
fruitMap.set('purple', ['grape', 'plum']);
function getFruitsByColorMap(color) {
return fruitMap.get(color) || [];
}5. Use Array.every and Array.some for collective checks
Use every to verify that all items satisfy a condition and some to verify that at least one item satisfies it.
const fruits = [
{ name: 'apple', color: 'red' },
{ name: 'banana', color: 'yellow' },
{ name: 'grape', color: 'purple' }
];
const allRed = fruits.every(f => f.color === 'red'); // false
const anyRed = fruits.some(f => f.color === 'red'); // trueSigned-in readers can open the original source through BestHub's protected redirect.
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