Discover Lucky Numbers in a List with a One‑Line Python Trick
This article explains the concept of “lucky numbers” in an integer list—where a number’s value equals its occurrence count—and walks through a Python solution that progressively uses set, count, map, zip, filter, lambda and sorted, culminating in a concise one‑liner implementation.
Problem Definition
Given a list of integers, a "lucky number" is an element whose value equals its frequency in the list.
Step‑by‑step solution
1. Remove duplicates
Use a set to obtain the unique elements.
arr = [3,5,2,7,3,8,1,2,4,8,9,3]
unique = set(arr) # {1,2,3,4,5,7,8,9}2. Count occurrences
The list method count() returns the frequency of an element.
pairs = [(x, arr.count(x)) for x in unique]
# [(1,1), (2,2), (3,3), (4,1), (5,1), (7,1), (8,2), (9,1)]3. Filter lucky numbers
Replace the explicit loop with map, zip and filter, then sort.
m = map(arr.count, unique)
z = zip(unique, m)
f = filter(lambda x: x[0] == x[1], z)
s = sorted(f, key=lambda x: x[0])
print('Lucky numbers are:', [item[0] for item in s])
# Lucky numbers are: [1, 2, 3]4. One‑liner version
The whole logic can be expressed in a single statement.
print('Lucky numbers are:', [x for x in sorted(filter(lambda x: x[0]==x[1], zip(set(arr), map(arr.count, set(arr)))), key=lambda x:x[0])])Signed-in readers can open the original source through BestHub's protected redirect.
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