How to Retrieve All File Names in a Directory and Keep the Largest ZIP File Using Python

To list all file names in a specific folder, you can use the os.listdir function combined with os.path.isfile to filter only files, as shown in the first example.

<code>import os

def get_file_names(folder_path):
    file_names = []
    for item in os.listdir(folder_path):
        item_path = os.path.join(folder_path, item)
        if os.path.isfile(item_path):  # only process files, ignore directories
            file_names.append(item)  # add file name to list
    return file_names

folder_path = "your_folder_path"  # replace with your folder path
file_names = get_file_names(folder_path)
print(file_names)</code>

The script iterates through the directory, checks each entry with os.path.isfile , and collects the file names into a list.

A more concise approach uses a list comprehension to achieve the same result in a single line.

<code>import os

def get_file_names(folder_path):
    return [item for item in os.listdir(folder_path) if os.path.isfile(os.path.join(folder_path, item))]

folder_path = "your_folder_path"  # replace with your folder path
file_names = get_file_names(folder_path)
print(file_names)</code>

This version leverages the syntax [expression for item in list if condition] to filter and collect file names.

To keep only the largest ZIP file in a directory, you can list all ZIP files with glob.glob , sort them by size using os.path.getsize , and delete the rest.

<code>import os
import glob

# specify folder path
folder_path = "/path/to/your/folder"

# get all zip files in the folder
zip_files = glob.glob(os.path.join(folder_path, "*.zip"))

# sort by file size descending
zip_files.sort(key=os.path.getsize, reverse=True)

# keep the largest zip, delete others
for i in range(1, len(zip_files)):
    os.remove(zip_files[i])

print("保留最大的zip文件完成。")</code>