How to Solve Python Integer Rounding Problems with Simple Code

Introduction

Hello, I’m a Python enthusiast. In a recent chat group a user asked a basic Python rounding question, and the discussion produced several solutions.

Implementation Process

The initial solution attempted to return different values based on the absolute number, but it produced an incorrect result for input 30 (expected 3, got 4). The code was:

def brf_cnt(consume_number):
    if abs(consume_number) < 13:
        return 1
    elif 13 <= abs(consume_number) < 21:
        return 2
    else:
        return consume_number // 10 + 1

if __name__ == '__main__':
    consume_number = 33
    print(brf_cnt(consume_number))

A corrected approach uses math.ceil to round up:

import math
cl = math.ceil
nums = [10, 13, 20, 21, 30, 31, 33]
for i in nums:
    if i < 13:
        print(1)
    else:
        print(cl(i/10))

Another community member offered a similar solution, and the original asker later posted his own version:

def money_people(x):
    if x < 13:
        return 1
    else:
        return (x - 1) // 10 + 1

print(money_people(20))

This can be further simplified with a ternary expression:

def money_people(x):
    return 1 if x < 13 else (x - 1) // 10 + 1

All three implementations satisfy the problem requirements.

Conclusion

The article summarizes the Python rounding problem, provides multiple clear code solutions, and invites readers to join a Python learning group for further discussion.