Master Python DateTime Parsing: Quick Solutions for Complex Formats

1. Introduction

Hello, I am a Python enthusiast. Yesterday a member asked about handling a Python datetime string, as shown in the image below.

2. Implementation

Two similar methods were shared. The first answer provides the following code:

from datetime import datetime
d = 'Wed Aug 03 19:48:03 +0800 2022'
r = datetime.strptime(d, '%a %b %d %X %z %Y')
print(r)

The execution result is shown below:

A second contributor offered an alternative implementation:

from datetime import datetime
day = "Wed Aug 03 19:48:03 +0800 2022"
res = datetime.strptime("Wed Aug 03 19:48:03 +0800 2022", "%a %b %d %H:%M:%S +0800 %Y")
print(res)

The corresponding output is displayed in the following image:

A third, more concise answer was shared as an image:

All solutions successfully resolved the original datetime parsing issue.

Additionally, a reference table for datetime format symbols is provided (image below).

3. UTC to Beijing Conversion

def utc_to_datetime(india_time_str):
    """格林威治时间(UTC)转北京时间 "%Y-%m-%d %H:%M:%S"""
    if not india_time_str:
        return
    if 'Z' in india_time_str:
        india_format = '%Y-%m-%dT%H:%M:%S.%fZ'
    else:
        india_format = '%Y-%m-%dT%H:%M:%S'
    india_dt = datetime.datetime.strptime(india_time_str, india_format)
    local_dt = india_dt + datetime.timedelta(hours=8)
    local_format = "%Y-%m-%d %H:%M:%S"
    time_str = local_dt.strftime(local_format)
    return time_str

4. Summary

This article collected a basic Python datetime conversion problem, explained the issue, and provided concrete code implementations that helped the community solve it. Thanks to the contributors for their insights and code snippets.