Three Clever Python Tricks to Solve Complex Divisibility Puzzles

1. Introduction

Hello everyone, I am a Python enthusiast. A few days ago in the Python Star Group a senior member asked a basic algorithm question, which I am sharing here.

2. Implementation Process

Here I present three approaches that I find quite effective, inviting everyone to learn together.

Method One

This method comes from the senior member’s idea and code, shown below:

y = 1
while(True):
    if y % 2== y % 4 == y % 8 and y % 3== 0 and y % 7 == 0 and y % 9 == 0 and y % 5 == 4 and y % 6 == 3:
        print("篮子里总共有鸡蛋: %s(个)"%y)
        break
    y += 1

Although iterating values one by one is slower, it works; the next two methods optimize this algorithm.

Method Two

This method comes from another senior member’s idea and code, shown below:

a = 9
while True:
    if a%5 == 4 and a%7 == 0 and a%8 == 1 and a%9 == 0:
        print(a)
        break
    a += 9

This method increments by 9, which is faster than Method One. Now for an even quicker solution.

Method Three

This idea comes from another senior member, illustrated below:

The code can be simply modified as follows:

y = 63
while(True):
  if y % 2== y % 4 == y % 8 and y % 3== 0 and y % 7 == 0 and y % 9 == 0 and y % 5 == 4 and y % 6 == 3:
    print("篮子里总共有鸡蛋: %s(个)"%y)
    break
  y += 63

Just pay attention to one point, as shown:

Thus, the solution perfectly meets the fan’s requirement.

Conclusion

Hello, I am a Python enthusiast. Based on a fan’s question, this article demonstrates solving a value‑finding problem with Python, cleverly applying and progressively optimizing algorithms, helping the fan resolve the issue and deepening understanding of Python programming. Thanks to all contributors and participants for their ideas and code.