How to Download All Files with a Python Web Scraper: Step-by-Step Guide

This article walks through a Python web‑scraping solution for downloading individual files from a site, presenting the problem, multiple approaches, and a complete, ready‑to‑run script, while also offering tips for handling large data and avoiding IP blocks.

Python Crawling & Data Mining
Python Crawling & Data Mining
Python Crawling & Data Mining
How to Download All Files with a Python Web Scraper: Step-by-Step Guide

1. Introduction

Hello, I'm Pipi. A few days ago in the Python Diamond group a member asked a question about Python web crawling, which I share here.

He wanted to retrieve all files, but in practice could only fetch a single file.

2. Implementation

Classmate Ning provided a solution idea, as shown in the figure:

Solution diagram
Solution diagram

Later, Teacher Yuliang offered another method, illustrated below:

Alternative method
Alternative method

A direct one‑step solution is shown here:

One‑step solution
One‑step solution

Below is the complete code:

import requests
import time
from lxml import html
from lxml import etree

headers = {
    'user-agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/109.0.0.0 '
    'Safari/537.36'
}

def get_href_links(url):
    response = requests.get(url, headers=headers)
    page_content = response.content
    dom_tree = html.fromstring(page_content)
    href_links = dom_tree.xpath('//a/@href')
    return href_links

url = "https://mp.weixin.qq.com/s/BANHI5apQzlpeTTdLZAIvg"
urls = set(get_href_links(url)[1:-5])
mp3_d_url = 'https://res.wx.qq.com/voice/getvoice?mediaid={}'
for url in urls:
    response = requests.get(url, headers=headers)
    html_text = response.text
    selector = etree.HTML(html_text)
    voice_encode_fileid = selector.xpath('//mpvoice/@voice_encode_fileid')[0]
    name = selector.xpath('//mpvoice/@name')[0]
    d_url = mp3_d_url.format(voice_encode_fileid)
    response = requests.get(d_url)
    if response.status_code == 200:
        with open(name, 'wb') as f:
            f.write(response.content)
        print(f'{name} 下载成功!')
    else:
        print(f'{name} 下载失败!')
    time.sleep(1)  # 设置请求间隔时间为1秒,避免被封IP

The script successfully solved the fan's problem.

3. Conclusion

This article addresses a Python web‑crawling issue, providing analysis and a complete implementation to help solve it.

Tip: When posting large files in a group, consider data masking and share only demo (small) files, include reproducible code snippets, and attach error screenshots if needed.

Original Source

Signed-in readers can open the original source through BestHub's protected redirect.

Sign in to view source
Republication Notice

This article has been distilled and summarized from source material, then republished for learning and reference. If you believe it infringes your rights, please contactadmin@besthub.devand we will review it promptly.

PythonWeb Scrapinglxml
Python Crawling & Data Mining
Written by

Python Crawling & Data Mining

Life's short, I code in Python. This channel shares Python web crawling, data mining, analysis, processing, visualization, automated testing, DevOps, big data, AI, cloud computing, machine learning tools, resources, news, technical articles, tutorial videos and learning materials. Join us!

0 followers
Reader feedback

How this landed with the community

Sign in to like

Rate this article

Was this worth your time?

Sign in to rate
Discussion

0 Comments

Thoughtful readers leave field notes, pushback, and hard-won operational detail here.