How to Parse Complex Python Strings with List Operations and Regex

In a recent Python community discussion, a user asked how to process a list of strings containing mixed text and URLs. The goal was to extract meaningful parts using list operations and regular expressions.

First, a simple approach splits each item at the ')' character and builds a new list:

lst = [元素列表]
# print(len(lst))
new_lst = [lst[0]]
for item in lst[1:]:
    new_item = item.split(')')
    new_lst.extend([new_item[0], new_item[1]])
print(len(new_lst))
print(new_lst)

This yields the expected result.

Another contributor provided a more compact solution combining two methods:

l1 = sum([*map((lambda x: x.split(')') if 'png)' in x else [x]), lists)], [])
l1 = [x for x in l1 if x != '']
l2 = []
nums = []
for j, item in enumerate(l1):
    if 'png' in item:
        if item[0] != '!':
            b = ' '.join(l1[j-1:j+1]).split('![](')
            nums.append(j)
        else:
            b = item.split('![](')
            b = [x for x in b if x != '']
        l2.extend(b)
    else:
        l2.append(item)
lists = [l2[j] for j in range(len(l2)) if j+1 not in nums]

Finally, a regular‑expression solution quickly extracts the desired substrings:

import re
data = 'your string here'
temp = re.findall(r'>(.*?)<|src="(.*?)"', data)
result = [i.replace('\u3000', ' ') for j in temp for i in j if i != '']
print(result)

The article concludes that these snippets demonstrate how to handle complex string parsing in Python, and thanks the community members who contributed.